Try this basic reasoning test.
Suppose there are four double-sided cards laid out next to each other on a table, like this: (|...| indicates the border of each card and has nothing to do with the content of each card.)
| I | | T | | 8 | | 5 |
Now consider the following rule:
(R) If there is a vowel on one side, there is an even number on the other.
-Objective:
Flipping over as few cards as possible, which cards would you have to turn over to see if the rule was true of these four cards?
I guess someone already got it but I'll post before I look at all the answers.
You need to flip two cards.
(R) is "If V, then E".
You need to flip the | I | card.
Justification: to test (R).
You need to flip the |5| card.
Justification: (R) implies "if not-E, then not-V" by modus tollens.
Since 5 is an odd number (or not-E), then the flip side must be a consonant (or not-V).
You do NOT need to flip | T |
Justification: (R) does not imply "if not-V, then not-E".
You do NOT need to flip | 8 |
Justification: (R) does not imply "if E, then V".
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Correction: I was assuming that on every card there is a letter on one side, and a number on the other. But since this is not the case, then you would need to also flip | T | since it is also "not-E" and the flip side must be "not-V" (a consonant or a number).
So my answer then is three cards: | I | | 5 | | T |, since 'I' is a vowel, and '5' and 'T' are not even numbers. Since '8' is an even number, anything can be on the reverse side and not violate the rule.
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